Nuprl Definition : fpf-sub 0,22

f  g == x:Ax  dom(f x  dom(g) & f(x) = g(x
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clarification:

fpf-sub(Aa.B(a); eqfg)
== x:A. fpf-dom(eqxf fpf-dom(eqxg) & fpf-ap(feqx) = fpf-ap(geqx B(x
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Definitionsx:AB(x), P  Q, A & B, b, x  dom(f), f(x)
FDL editor aliasesfpf-sub

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